Question

Help? I kinda don't get this.

Answer 1

HEY:P

Answer 2

when x = 8 .. what is the value of y ?
look at the graph what is the value of the graph when x =8

Answer 3

x=-8 **

Answer 4

yes ! 2 !

Answer 5

yes lol

Answer 6

yes

Answer 7

pretty easy isnt it ?

Answer 8

excluded means the values that x cant get ..
we are not allowed to divide by zero
for what values of x we divide by zero ?

Answer 9

are you there ? trying ?

Answer 10

we cant have zero in the denominator ..

Answer 11

so for the first fraction we have x/(x-2)
it means x -2 cant be zero
so it means x cant be 2..
the second fraction 1/(x-4)
so what x cant be ?

Answer 12

sorry i had to go

Answer 13

no see if
x-4 = 0
so x =4

Answer 14

so x cant be 2 and cant be 4

now we look at the denominator of the last fraction
x^2-6x+8
we have to see for what x values we get here 0
can you find them ?

Answer 15

very good!!
so again x is not 2 and not 4..
so finally the excluded values are 2 and 4

Answer 16

:)

Answer 17

yw