Hey guys, I'm having a lot of trouble with inverse trig functions. It's just the concept that's confusing, I was wondering if someone could work a problem for me?

cos(sin^-1 1/2)

Question

Hey guys, I'm having a lot of trouble with inverse trig functions. It's just the concept that's confusing, I was wondering if someone could work a problem for me? 

cos(sin^-1 1/2)

anonymous · Answer

first you work with sin ^-1  1/2 and this is 30 
then cos 30 = $$\sqrt{3}/2$$   thats all ^^