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Find the sum of the infinite geometric series: 9 – 6 + 4 – …
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use formula : S = a/(1-r) for a = the first term r = ratio
The thing is I don't know how to find r
r = a2/a1 = -6/9 = -2/3
so, S = 9/(1-(-2/3)) = 9/(1+2/3) = 9/(5/3) = ... ?
or u can write into multiplication : 9 * (3/5) = ...
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