what is the solution of the system equation? -2x+y=3 8x-4y=-12
First solve for y in the first equation
Can you do it?
yeah its y=-2x+3
Watch your negative sign
Do you want to use elimination method or substitution method to solve this problem?
substitution
Okay, retry to solve the first equation for y.
idk cause thats how i thought u do it
-2x + y = 3 +2x -2x + y = 3 + 2x y = 3 + 2x
are u sure??
You have to reverse the sign
yes
okay nvm i see how u did it
now we will substitute this into the second equation
8x - 4(3 + 2x) = -12
ok
can you solve for x by yourself now?
i got 0
There is something wrong. Double check your problem and make sure you typed the original correctly 8x - 12 - 8x = -12 0=0 The x term drops out completely, this shouldn't happen
yeah i guess so thats why i ased cause i was getting confused
I want to go back to this equation 8x - 12 - 8x = -12 rewritten as 8x - 12 = 8x - 12 lets get rid of the -12 8x = 8x then the 8's x=x So we can see that x equals all real numbers
This question is written badly. You are positive this is the correct question?
yes
I'm going to admit that I am confused as to our answer as well. Because x can equal anything which gives us an infinite amount of solutions. x=y/2 - 3/2 8(y/2 - 3/2) - 4y = -12 4y -12 - 4y = -12 y can be anything as well I'd say there is any infinite amount of solutions
This is a weird problem. Sry that I couln't help get an exact answer. All of our steps our correct, we didn't make any mistakes
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