Question

One number is five more than twice another. If their sum is decreased by ten, the result is twenty two . Find the numbers

Answer 1

"twice another"
2y
"five more than"
+5

2y+5 = x
There's one equation.

"Their sum"
x+y
"is decreased by 10
-10
x+y-10 = 20
There's your second equation.

Answer 2

the second, should be x+y-10 = 22

Answer 3

Oh, right. Thank you.

Answer 4

Let one number=x
Other number=y

Condition 1:One number is five more than twice another
Twice the other number=2y
Therefore, x = 2y + 5 (1st Equation)

Condition 2:If their sum is decreased by ten, the result is twenty two
Their sum=x + y
Sum decreased by '10' = (x + y) - 10
Therefore,
(x + y) - 10 = 22 (2nd Equation)

Solving both the equations we get,
x=23
y=9