Question

x^8=y^2+87
Find all the values of x and y for which x and y are prime numbers.

Answer 1

..........

Answer 2

hehehehe u thought u where gonna get the answer xD

Answer 3

Sorry, but I know the answer as this question is mine.

Answer 4

Oh...

What an easy question..!

I don't want to solve it..

Ha ha ha ha...

Answer 5

ahahahaha

Answer 6

Sorry the question is little changed.

Answer 7

is this allowed ?
(x^4-y)(x^4+y) = 87

since it's either 87*1 or 29*3
we need
x^4-y =1
and
x^4+y=87
we wont get here prime number for x

or
x^4-y=3
x^4+y=29

2x^4 = 32
x^4 = 16
x = 2 y = 13


so only x = 2 and y = 13 ?

Answer 8

Ya...... that looks correct.