Question

2 - limit (as t approached negative infinity) t^2 * e^t + 2e^t *t - 2e^t
If you could tell me the steps to solve and why, which I believe will involve the l'hospital's rule, that would be most excellent.

Answer 1

\[2 - \lim_{t \rightarrow -\infty} t^2e^t + 2e^t(t) - 2e^t\]
That probably makes it easier to visualize.