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find all solutions for cos z = 2, z=x+iy?
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2-iy = x
2-x/i = y
2-x/y = i
you need to start with \[\frac{1}{2}(e^{iz}+e^{-iz})=2\]
then to \[e^{iz}+e^{-iz}=4\] and then \[e^{2iz}+4e^{iz}+1=0\] solve the quadratic equation in \(e^{iz}\)
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typo i mean \[e^{2iz}-4e^{iz}+1=0\]
ohh. ic. thx.
yw
cos never be 2 in maths
-1<cosx<1
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