Question

What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?

Answer 1

EQUATION OF GIVEN LINE IS
y=-x-3
its slope is -1
thus aline perpendicular to it has a slope = -1/-1 = 1
now the point is (2,3)
using point slope for we get
y-y1=m(x-x1)
y-3= 1(x-2)
=>y=x-2+3

=>y=x+1------------>required equation

Answer 2

thanks!