Question

explain why the solution set of x^2+16<0 is empty?

Answer 1

because x^2+2 is definite positive, so no x satisfy it be negative solution

Answer 2

sorry, x^2 + 16 i mean

Answer 3

thank you but how can I explain further because I have to put it in a explanation like first show the solution set of equaling both sides 4 4?

Answer 4

ok, look the equation x^2+16
if we take x real (all positive numbers, negative numbers and 0), then
x^2+16 always be a positive number, in quadratic equation wass call a definite positive function