Your piggy bank has a total of 47 coins in it; some are dimes and some are nickels. If you have a total of $3.95, how many nickels do you have? @JakeV8
dimes are 10 cents each and nickels are 5 cents each right?
the first two equations would be n+d=47 & .05n+.10d=3.95 but idk how to get the rest
solve them by elimination or substitution
substitution : n = 47 - d , then substitute this n into the other equation. elimination : .05 n + .1 d = 3.95 times 20 = n + 2d = 79.0 n + 2d = 79 n + d = 47 minus them :x
i dnt understand...
n + d = 47 --> n = 47 - d then put n above into 0.05n + 0.1d = 3.95
.05(47-d)+0.1d=3.95 2.35-.05d+0.1d=3.95 2.35+.05d=3.95 -2.35 -2.35 .05d=1.6 /.05 /.05 d=32 ???? did i do it correctly? then it would be 47-32=15 n=15 ??
@nphuongsun93
yup that's right
thx!
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