Question

AP physics free response help!

Answer 1

I do not understand question 1 part b http://apcentral.collegeboard.com/apc/public/repository/ap09_frq_physics_b_formb.pdf

Answer 2

\[(P = 2 \pi \sqrt{\frac{ m _{1}r }{m _{2}g }} )^2*\frac{ m _{2}g }{ P^2 }\]
\[ 4 \pi^2 \frac{ m _{1}r }{P^2} =m _{2}g \]

Answer 3

I got that @Algebraic! But I don't get the graphing of a straight line to determine slope g

Answer 4

use the values given and plot 4pi^2*(m1r/P^2) vs m2

Answer 5

But in the solution it says the last row is 1/p values

Answer 6

slope is 10. so far...

Answer 7

I see where this is going! thank you!