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Mathematics 21 Online
OpenStudy (anonymous):

x/3+ 2x/15< 2/3

OpenStudy (anonymous):

you need a common denominator to add the fractions on the left of the inequality. Try 15... \[(\frac{ x }{ 3 })(\frac{ 5 }{ 5 }) + \frac{ 2x }{ 15 }< \frac{ 2 }{ 3 }\] \[\frac{ 5x }{ 15 } + \frac{ 2x }{ 15 }< \frac{ 2 }{ 3 }\] \[\frac{ 5x + 2x }{ 15 } < \frac{ 2 }{ 3 }\]

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