Question

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Answer 1

For each one, solve one of the systems first for x or y =, then substitute back in
for example, first one 2x+5y=-5 and x+3y=3
we can solve the 2nd equation for x, x = 3-3y
then plug into equation one as x
2(3-3y)+5y = -5
then you'll only have 1 unknown (y in this case)
solve for y, then plug back into your 2nd equation for x.