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Solve using law of cosines a = 12, b = 14, c = 21
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Do you know the formula for law of cosines?
yea i did it but i wanna know if i got it right 12^2 = 14^2 + 21^2 – 2(14)(21) cosA 144 = 196 + 441 – 588 cosA 144 = 637 – 588 cosA -637 -637 -493 = -588 cosA -588 -493/-588 = cosA cos^-1(493/588) = 33.02
That looks correct to me.
ok :)
ok :)
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