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Find the exact value of cos(u+v) given that sin u =7/25 and cos v = -12/13 (both u and v are in Quadrant 2). I am stuck with getting 288/325.
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-209/325
7/25-12/13=-209/325
should be 253/325
how?
My answer key said that was the answer. You could be correct. :) My book uses Cos (v-u).
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\[\frac{ 7 }{ 25 }*\frac{ 13 }{ 13 }-\frac{ 12 }{ 13 }*\frac{ 25 }{ 25 }\]
cos(-209/325)=0.8002
my book does it differently...but, I see what you did. You are likely right.
what grade is this?
Trig
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(-24/25)(-12/13)(7/25)(18/13)
?/325
where did all of these numbers come from
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