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Mathematics 12 Online
OpenStudy (anonymous):

Could anyone help me find this derivative?

OpenStudy (anonymous):

OpenStudy (baldymcgee6):

as this is a quotient, it is intuitive to use the quotient rule.

OpenStudy (baldymcgee6):

h'(x) = ((tan(3x))'*x^2 - tan(3x)*(x^2)')/(x^2)^2

OpenStudy (anonymous):

I got this (3 x^2 sec(2)-2 tan(3 x))/x^3

OpenStudy (baldymcgee6):

what is the derivative of tan(x)?

OpenStudy (anonymous):

sec^2x?

OpenStudy (baldymcgee6):

yes, so you need to fix that.

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