Question

g(t)= -t^2 - 2t
h(t)= 3t-3
Find (g-h)(t+2)
i just need to see if my answer is correct.

Answer 1

@jim_thompson5910 thia one is really challenging.

Answer 2

this*

Answer 3

hint:

(g-h)(t+2)

is the same as

g(t+2) - h(t+2)

Answer 4

I know but the algebra sometimes trips me up. my final answer came out to t^2-9t-9 but i have a feeling i messed up somewhere along the line

Answer 5

that's pretty close, but not quite correct

Answer 6

ahh darn

Answer 7

g(t)= -t^2 - 2t

g(t+2)= -(t+2)^2 - 2(t+2)

g(t+2)= -(t^2+4t+4) - 2(t+2)

g(t+2)= -t^2-4t-4 - 2t-4

g(t+2)= -t^2-6t-8

---------------------------------

h(t)= 3t-3

h(t+2)= 3(t+2)-3

h(t+2)= 3t+6-3

h(t+2)= 3t+3

===========================

(g-h)(t+2)

g(t+2) - h(t+2)

(-t^2-6t-8) - (3t+3)

I'll let you finish

Answer 8

whew is it -t^2 -9t-5

Answer 9

close, but - (3t+3) becomes - 3t-3

Answer 10

NOT -3t + 3

Answer 11

oh so is it -t^2 -3t -5 ?

Answer 12

no

Answer 13

(-t^2-6t-8) - (3t+3)

-t^2-6t-8 - 3t-3

Answer 14

keep going

Answer 15

let's try again. -t^2-9t-11 or -t^2-3t-11

Answer 16

-6 - 3 = ??

Answer 17

-9

Answer 18

so -6t - 3t = -9t

Answer 19

it's the first one

Answer 20

thanks so so so so so much for bearing with me and not stabbing your eyes out.

Answer 21

lol i like my eyes, so I wouldn't do that, but yw