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Mathematics 13 Online
OpenStudy (anonymous):

Does ((-1)^n)/n^2 converge?

OpenStudy (anonymous):

yeah. use the test for convergence

OpenStudy (anonymous):

for alernating series

OpenStudy (anonymous):

n>M->abs(-1^n/n2)=1/n2<1/M2

OpenStudy (anonymous):

It shows it is converged.

OpenStudy (anonymous):

Thanks, the limit of the magnitude of the function as n approches infinite is zero so it is convergent

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