How do you represent the (decimal) integer 50 in, oh, "hexadecimal," otherwise known as base-16? Recall that decimal is simply base-10, and binary is simply base-2. Infer from those base systems how to represent this one!

Question

anonymous · Answer

All you have to do is divide the integer (50) by 16 to get the hexadecimal form. If you get a remainder greater than 9 name them with A or B or likewise.. :)

anonymous · Answer

You might want to use the modulus function, which returns the value of the remainder.

rsmith6559 · Answer

Here's a little recursive function in Python to convert a base 10 number to any base between 2 and 35, ( the calling program has to check the base's value ):

characters = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"

def mkDigit( number, base ):
	if( number == 0 ):
		return ""
	index = number % base
	number = number // base
	return mkDigit( number, base ) + characters[ index ]