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0, 2, 8, 26, 80, 242, 728, 2168, 6560, 19682 write a recursive formula or explicit formula?
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Hint: each of them increase by \[2 \times 3^{(n-1)}\]
2168 should be 2186
Thus the recursive formula will be\[A_{1}=0...and...A_{n}= 3A_{n-1}+2\]
A_n = [3 ^ (n-1)] - 1 for 1 <= n < = 10
TQ :)
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