Question

For what point on the curve of y=9x^2-5x is the slope of a tangent line equal to 49? Any help greatly appreciated :)

Answer 1

differentiate this curve and make it equal to 49.. solve for x :P

Answer 2

first, to find a tangent, we differentiate the equation.
\[\frac{ dy }{ dx } = 18x-5\] This is the tangent value of the x point on the curve.

Answer 3

As vikrang said, since the value of tangent is given, just find it backwards.

Answer 4

I got x=3

Answer 5

yup! nice one! :)

Answer 6

So that's all there was to it? lol.

Answer 7

Yup! Understanding what the question wants can bring quick answers.