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Mathematics 13 Online
OpenStudy (anonymous):

solve x^2 -x -12=0

OpenStudy (anonymous):

x=1 or x= 12?

OpenStudy (anonymous):

\[x^2-x-12=0\]\[x^2-4x+3x-12=0\]So it won't be x=1 or x=12..

OpenStudy (zzr0ck3r):

you can always check your answers x = 1 1^2 -1 -12 != 0 x=12 12^2 - 12 -12 = 144-24 = 120 != 0

OpenStudy (anonymous):

Give a try... :)

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