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Let y = 4*sqrtx Estimate the difference delta y when x = 5 using a linear approximation , given that delta x = 0.3
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@TuringTest I forgot my linear approximations.
This is phrased strangely for me, but I assume they want you to do is say for \(x\approx x_0=5\) we have that\[y(x)\approx y(x_0)+y'(x_0)(x-x_0)\implies y(x)-y(x_0)\approx y'(x_0)(x-x_0)\]\[\Delta y=y(x)-y(x_0),~~~~\Delta x=x-x_0=0.3\]therefor\[\Delta y\approx y'(5)\Delta x\]
@sam0102493 let me know if that makes sense to you
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