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in what base does 10=57 base 8 and 11=31 base 4? And why?
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may i knw if they're two different questions or both are one q only
They are actually two different questions.
\[\rm 5\cdot 8 + 7 \cdot 1 = 47 \]
thank you :) Q1 : \((10)_x = (57)_8\) Q2 : \((11)_y = (31)_4\)
see parth's hint... you wil be able to figure out....
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\[\rm (10)_x = 57_8 \implies 1x^1 + 0x^0 = 57_8 \implies x = 57_8\]
That's a ridiculous base. lol
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