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Eliminate the parameter t to find the cartesian equation of this curve. Find the points on the curve at which the tangent line is horizontal or vertical. Let x=2t-t^2 and y=-t+t^2
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Try solving for t on one of the equations.
(Then substitute the answer into your other equation.)
x=t(2-t) and y=t(t-1), can i plug in two different values for t, like t=y, t=y+1?
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