Question

How do I solve this equation: ln(x+1)/ln(x-1) = 2?

Answer 1

that equation can be written as: \(\large ln(x+1)=2ln(x-1) \)
or

\(\large ln(x+1)=ln(x-1)^2 \rightarrow (x+1)=(x-1)^2\)

agreed?

Answer 2

yup

Answer 3

so can you solve that last equation: \(\large (x+1)=(x-1)^2 \) ???