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find the inverse function of f(x)=x^2-8 , x<0
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i am positve it is square root x+8 but my math lab hw is saying its wrong
i idd
(x,y) becomes (y,x) in an inverse functions, which means that you have to replace the signs.\[\rm x = y^2 - 8\]
got it thanks yall
invers of quadratic function is squareroot function, @ParthKohli
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oh, he was offline
nices sites, @nincompoop what should the answer ?
yea, i agree... how about with x<0 ?
\[\sqrt{(x+8)}\]
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