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OpenStudy (anonymous):
z^2+9=10z I rewrote it as z^2-10z+9=0 but I don't understand what to do next
can anyone please help me?????? thanks for nothing folks
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OpenStudy (ajprincess):
What do u get when u multiply 16 by 81 @leslieJampolsky?
OpenStudy (anonymous):
1296
OpenStudy (ajprincess):
Can u tell me two factors of 1296 such that their sum is 72?
OpenStudy (anonymous):
36X36=1296 and 36+36=72
OpenStudy (ajprincess):
yup u r right:)
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OpenStudy (anonymous):
I got to : 16x+36x+36x+81 but I don't know what to do next
OpenStudy (ajprincess):
Try to factorise 16x^2+36x and 36x+81.
What do u get when u factorise them @leslieJampolsky?
OpenStudy (anonymous):
4x(4x+9) +9(4x+9)
OpenStudy (anonymous):
4x(4x+9)1(36+81) but I think that is wrong
OpenStudy (anonymous):
to uzumakhi: so to simplify even more would it read: x(4x+9)(4x+9)????
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OpenStudy (anonymous):
no its (4x+9)^2
OpenStudy (ajprincess):
16x^2+36x=4x(4x+9)
36x+81=9(4x+9)
16x^2+36x+36x+81=4x(4x+9)+9(4x+9)
=(4x+9)(4x+9)
=(4x+9)^2
Getting this @leslieJampolsky?
OpenStudy (anonymous):
Notice how \(4x\cdot4x = 16x^2\) and \(9\cdot9 = 81\) and \(2(9+4x) = 72x\)
OpenStudy (anonymous):
thank you all so much
OpenStudy (ajprincess):
yw:)
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