Question

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 2.1 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?

can you explain this question to me thanks!!

Answer 1

you want to find dy/dt

Answer 2

y= 24/x
differentiate with respect to time and plug in the value of x and dx/dt