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(sqrt 7x) times ((sq rt x)-7sq rt.7) is the answer x times sq rt 7 -49 times sq rt. x?
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\[\sqrt{7x}(\sqrt{x}-7\sqrt{7})=\sqrt{7}-7(7)\sqrt{x}=\sqrt{7}-49\sqrt{x}\]
not x times sq rt. 7?
don't I have x squared =x
no because\[\sqrt{7x}\sqrt{x}=\sqrt{7}\sqrt{x}\sqrt{x}=x \sqrt{7}\]
that's what I thought but you don't have x in front of sq rt 7 in your answer
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\[\sqrt{7x} \times (\sqrt{x}-7\sqrt{7})\]\[(\sqrt{7x} \times \sqrt{x})(\sqrt{7x} \times 7\sqrt{7})\]
is my answer not correct?
ohh ! i don't see that @Jonask has already helped u :)
why not x times sq rt.7 as part of answer
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