Question

A and B are constants such that (x+6)/x^2-3x = (A/x)+(B/x-3) . Find A-B.

Answer 1

so you need makeing the calcules by common denominator
so for from the first fraction from denominator factoriz out x and will get ?
can you calcule it ?

Answer 2

Could you possibly solve it showing step by step?

Answer 3

so will be

(x+6)/(x(x-3)) = (A/x ) +(B/(x-3)

yes ?

Answer 4

Would it be possible for you to solve the entire problem?

Answer 5

how do you think it ?

i like help you understanding how you need solving the same exercises correct

ok ?

Answer 6

so but you need cooperating what you know

ok ?

Answer 7

I'm helping someone out with this and I've been away from this type of math for years..that's why I was asking for a step by step, so I could explain it

Answer 8

ok so can you write here the needed calcules how you think it right ?

Answer 9

so than no

in the first step

(x+6) A B
------ = --- + ------
x(x-3) x x-3

this is ok ,yes ?

Answer 10

yes

Answer 11

so than on the right side we need calcule the common denominator so what will be x(x-3) and for we can assuming these terms we need multiplie A by (x-3) and B by x and will get

(x+6) (x-3)A + xB
------- = -----------
x(x-3) x(x-3)

so there are on both sides the same ,equales common denominators than we can making the numerators equales the same and will get

(x+6) =(x-3)A +xB make the calcule on the right side

(x+6)=xA-3A +xB factoriz out the x and will get
(x+6)=x(A+B) -3A assum to both sides 3A
x+6+3A=x(A+B) divide both sides by x

(x+6+3A)
--------- = A+B
x

so but you need to find A-B

how ?

Answer 12

opinion ?

Answer 13

so add to both sides -2B and will get it

(x+6+3A)
--------- -2B = A+B -2B
x

(x+6+3A-2B)
------------- = A -B
x

ok ?

Answer 14

Great - thanks for all your help...greatly appreciated!

Answer 15

was my pleasure

yw

so you have thougt it the same ?