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DOUBLE INEQUALITY?? Please help me solve this: |x-1|<|x-3|
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@Studentc14 For these squaring both sides is one method. Example:\[\left| x +4 \right|<\left| 2x -6 \right|\]Squaring both sides yields\[x ^{2}+8x +16<4x ^{2}-24x +36\] \[0<3x ^{2}-32x +20\] \[3x ^{2}-32x +20>0\] \[(3x -2)(x -10)>0\] |dw:1350872401427:dw| ∴x < 2/3 or x > 10 Now you try your question and see if you understand?
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