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Mathematics 15 Online
OpenStudy (anonymous):

find zero from y=x^2+x-12

OpenStudy (anonymous):

y=(x+4)(x-3) what are the zeros?

OpenStudy (anonymous):

i have to find zero i believe it is -4,3 and y=-0.5

OpenStudy (anonymous):

thats what i got

OpenStudy (anonymous):

x=-4, x=3 are correct

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