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OpenStudy (anonymous):
find zero from y=x^2+x-12
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OpenStudy (anonymous):
y=(x+4)(x-3) what are the zeros?
OpenStudy (anonymous):
i have to find zero i believe it is -4,3 and y=-0.5
OpenStudy (anonymous):
thats what i got
OpenStudy (anonymous):
x=-4, x=3 are correct
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