Question

find number of binomial with x^2-18x+_____=(____)^2

Answer 1

18/2=9
9^2=81

x^2-18x+81=(x-9)^2

Answer 2

so its -18;x-18

Answer 3

no i ment 81 and -9

Answer 4

you need to complete the square

ax^2 + bx + c

c= (b/2)^2
in your case (-18/2)^2 = (-9)^2 = 81

Answer 5

OK i understand it a lot better now thanks a lot :)