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What would be the resistance of a piece of aluminium wire 1.8 mm in diameter and 10 m long?(The resistivity of aluminium is 2.8 × 10–8 Ω m.)
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\[R=\rho L/A\]
Yes so for A I did... π * ((0.9)^-3)^2 and got 5.91 m^2
Is that correct? :o
if you mean \(A=\pi\times(0.9\times10^{-3})^2\), you're correct.
Oops now I realise why I've got the wrong answer... I forgot to add in the x10 bit :P Thank you
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