Question

F(x) = 1/(x^2-4), such that F''(x) = (6x^2-8)/(x^2-4)^3
I am asked to find the intervals of concavity and possible points of inflection. But....

Answer 1

When i set F''(x)=0 then i get a value (+-2/sqrt(3)) and WOLF says that this graph has no points of inflection (because it is asymptotic). What am i misunderstanding?

Answer 2

The minus sign in the numerator of F'' should be a plus sign. That makes the numerator always >0.

Answer 3

Let me know if you're on line at he same time I am and I'll explain.