Question

\[\large \rm \sin(x) = \tan(x)\]

Answer 1

So I assume that the next step is writing it like this or what?\[\rm \large {\sin (x)} = {\sin(x) \over \cos (x)}\]

Answer 2

Hmm... let me think\[\rm \large \sin(x)\cos(x) = \sin(x)\]\[\rm \large \sin(x)\cos(x) - \sin(x) = 0\]Ohhhh.

Answer 3

\[\rm \large \sin(x) (\cos(x)- 1) =0\]I think I'd manage. thanks