Question

Can someone show me how to find the Zeros from this equation x^3-2x^2-x+2

Answer 1

\[x ^{3}-2x ^{2}-x+2=0\]

Answer 2

Do you remember factoring in pairs?

Answer 3

such as \[x ^{3}-x and -2x ^{2}+2\]

Answer 4

\[x^3-2x^2-x+2=0\\
x^2(x-2)-(x-2)=0\\
(x^2-1)(x-2)=0\\
(x+1)(x-1)(x-2)=0\\
x+1=0\lor x-1=0\lor x-2=0\\
x=-1\lor x=1\lor x=2\]

Answer 5

ok I got that thank you so much for your helpe!

Answer 6

Factor:
\[x ^{3}-2x ^{2}\]
Factor:
\[-x+2\]

Answer 7

By factoring for the last one, I mean:

\[-1(x+2)\]