Question

how many nonreal zeros does y=2x^3-x^2+10x-5 have

Answer 1

2x^3 -x^2 +10x -5=0
x^2(2x-1) +5(2x-1)=0
(x^2 +5)(2x -1)=0

x^2 +5=0
x^2 =-5

x_1,2=+/-sqrt(-5) =+/- isqrt5 so these will be the non real zeros

2x-1=0
2x=1

x=1/2

hope so much that is understandably

good luck

bye