Solve by using tables. Give each answer to at most two decimal places.
–2x^2 – 4 = –8x

0.59, 3.41
–3.41, –0.59
1.17, 6.83
–1.41, 1.41

Question

Solve by using tables. Give each answer to at most two decimal places.
–2x^2 – 4 = –8x 


0.59, 3.41
–3.41, –0.59
1.17, 6.83
–1.41, 1.41

jiteshmeghwal9 · Answer

$$-2x^2-4+8x=0$$$$-2x^2+8x-4=0$$$$-(8) \pm \sqrt{(8)^2-4(-2)(-4)}\over2(-2)$$

jiteshmeghwal9 · Answer

solve this to gt ur answer :)

anonymous · Answer

I have tried to solve that and its not working out :/

anonymous · Answer

Enter the problem into your graphing calculator's Table program. http://puu.sh/1hM6X

anonymous · Answer

i dont have a graphing calc :/

anonymous · Answer

I got 2 plus square root 2 or 2 minus square root of 2.   Given square root of 2 is about 1.4  that gives about 0.6 and 3.4 as results

anonymous · Answer

Then you must solve by hand.
$$
–2x^2 – 4 = –8x\
2x^2-8x+4=0\
x^2-4x+2=0\
x=\frac{4\pm\sqrt{8}}{2}\
\ \ =2\pm\sqrt2
$$

anonymous · Answer

Solve by using tables. Give each answer to at most two decimal places.
–2x2 – 4 = –8x  (1 point)
  (1 pt) 0.59, 3.41
  (0 pts) –3.41, –0.59
  (0 pts) 1.17, 6.83
  (0 pts) –1.41, 1.41
1 /1 point