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Mathematics 17 Online
OpenStudy (anonymous):

i am so confused x^2-4x+___-(____)^2

OpenStudy (anonymous):

have to find number and binomial

OpenStudy (anonymous):

i think that your supposed to find things that multiply that equal it

hartnn (hartnn):

there is a method for completing the square: step 1: make co-efficient of x as 1 (ts already 1 here) step 2 : identify the co-efficient of x (the number besides x) what is it here?

OpenStudy (anonymous):

-4 ?

hartnn (hartnn):

that is correct. step 3: now half it. what u get ?

hartnn (hartnn):

means divide it by 2

OpenStudy (anonymous):

-2

hartnn (hartnn):

step 4: now square it, what u get ?

OpenStudy (anonymous):

4

hartnn (hartnn):

that is correct . sorry, i mistyped step 1 as 'step 1: make co-efficient of x as 1 (ts already 1 here)' it should be 'step 1: make co-efficient of x^2 as 1 (ts already 1 here)' step 5 : now add and subtract 4 in x^2-4x+... what u get ?

OpenStudy (anonymous):

4 , x-2

OpenStudy (anonymous):

you shouldn't just give me the answer

hartnn (hartnn):

just to be sure , the question is x^2-4x+___= (____)^2 right ? then step 4 is the answer to the number on left

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thanks for your help

hartnn (hartnn):

so u should follow the steps 1 through 4 for getting the number....now u know how to get binomial ?

OpenStudy (anonymous):

yes thanks

hartnn (hartnn):

welcome ^_^

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