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OpenStudy (anonymous):
have to find number and binomial
OpenStudy (anonymous):
i think that your supposed to find things that multiply that equal it
hartnn (hartnn):
there is a method for completing the square:
step 1: make co-efficient of x as 1 (ts already 1 here)
step 2 : identify the co-efficient of x (the number besides x)
what is it here?
OpenStudy (anonymous):
-4
?
hartnn (hartnn):
that is correct.
step 3: now half it. what u get ?
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hartnn (hartnn):
means divide it by 2
OpenStudy (anonymous):
-2
hartnn (hartnn):
step 4: now square it, what u get ?
OpenStudy (anonymous):
4
hartnn (hartnn):
that is correct .
sorry, i mistyped step 1 as 'step 1: make co-efficient of x as 1 (ts already 1 here)'
it should be
'step 1: make co-efficient of x^2 as 1 (ts already 1 here)'
step 5 : now add and subtract 4 in x^2-4x+...
what u get ?
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OpenStudy (anonymous):
4 , x-2
OpenStudy (anonymous):
you shouldn't just give me the answer
hartnn (hartnn):
just to be sure , the question is
x^2-4x+___= (____)^2
right ?
then step 4 is the answer to the number on left
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
thanks for your help
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hartnn (hartnn):
so u should follow the steps 1 through 4 for getting the number....now u know how to get binomial ?