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Equation in vertex form is y= a(x-h)^2 +k where h,k is the vertex of the parabola drawn. can u find the co-ordinates of vertex from the graph ?
150?
the vertex is a pair of points (h,k) where this graph hits its maximum at which point is this graph max ?
sorry I mean 50,150
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yeah, thats correct, so h=50, k = 150 now you only need a any ideas how to get it....
2/3
nopes, how did u get that ?
wait is it 50/30
u have point 0,0 which lie on this curve so just put x=0, y=0 in y= a(x-h)^2 +k and u already have h=50,k=150 so u get a
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0=a(0-50)^2+150 a=-150/50^2=?
9
-150/50^2 = -150/2500 = -15/250 = -3/50 so the final equation becomes y= - (3/50)(x-50)^2 +150
thx i think i get it some what :)
welcome ^_^
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