Question

...

Answer 1

whats the vertex form ..... from last question ?

Answer 2

nope its a new question

Answer 3

i know, but i gave u vertex form in last question... with vertex h,jk

Answer 4

h,k

Answer 5

how do i use it in this one?

Answer 6

first write down that equation here , what was it ?

Answer 7

y=a(x-h)^2+k

Answer 8

right , now put h,k = 5,-3 here
means put h=5,k=-3
what u get ?

Answer 9

y=a(x-5)^2+-3

Answer 10

correct.
now u have a point x,y=6,1 lying on this parabola
so put x=6, y=1 in that equation
y=a(x-5)^2-3
and u get a

Answer 11

1=a(6-5)^2-3

Answer 12

1=(1)^2-3

Answer 13

1=a(1)^2-3

Answer 14

1=a-3
a=?

Answer 15

4

Answer 16

yes, a=4
so final answer is ?

Answer 17

1=4(1)^2-3

Answer 18

u have h=5,k=-3,a=4
put it in y=a(x-h)^2+k to get the answer

Answer 19

y=4(x-5)^2-3

Answer 20

that is correct

Answer 21

It's be yay :D thx