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How do you factor q^3-8? I know it's something to do with 3 q's and 3 2's
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Yes, it's a difrerence of two cubes.
difference*
According to the formula,\[\rm \large a^3 - b^3 = (a - b)(a^2 + ab + b^2)\]
ok i can do it from there. ty!
You're welcome :)
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wait is the answer (q-2)(q^2+2q+2^2)?
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