find three consecutive integers whos sum is 240.
let x the first integer x+1 is the next consecutive integer and x+2 is the next consecutive integer after the second integer
the three consecutive integers must add to 240, so x+x+1+x+2 = 240
which simplifies to 240=3x+3 237=3x 79=x
the integers are: 79, 80, and 81
Hope this helped