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OpenStudy (anonymous):
Solve for x. x^x(lnx+1)=0
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OpenStudy (australopithecus):
there is no Real solution to this problem
OpenStudy (australopithecus):
unless that is \[x^x(lnx + 1) = 0\]
OpenStudy (australopithecus):
x^x(lnx+1)=0 (ln(x) + 1) = 0 ln(x) = -1 x = e^(-1)
OpenStudy (australopithecus):
I divided away x^x
OpenStudy (australopithecus):
as x^x =/= 0
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OpenStudy (anonymous):
okay gotcha. I was wondering where the x^x went to. Thank you!
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