Question

Solve for x.

x^x(lnx+1)=0

Answer 1

there is no Real solution to this problem

Answer 2

unless that is
\[x^x(lnx + 1) = 0\]

Answer 3

x^x(lnx+1)=0
(ln(x) + 1) = 0
ln(x) = -1
x = e^(-1)

Answer 4

I divided away x^x

Answer 5

as x^x =/= 0

Answer 6

okay gotcha. I was wondering where the x^x went to. Thank you!