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10x^2-x-2=0 a, -240;two real solution b,21 ;two imaginary solution c,81;two real solution d,-3;two imaginary solution
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look at the discriminant ie b^2-4ac or in this case (-1)^2-4(10)(-2). as you can see it is equal to positive 81 which implies that the roots are real as there is no square rooting of a negative number when using the quadratic formula
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