Question

simple math question: in a substitution (calculus) where du=(x-1)dx, can I add 1 one both sides to get du+1=xdx ? or do the dx prevent it since it multiplies (x-1) ?

Answer 1

if you expand du = (x - 1)dx, you should get du = xdx - dx (according to distributive property)

does that answer your question?

Answer 2

yes thank you !