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Triple Variable System Help? 4x-y+z=0 -2x+2y+3z=3 -x+3y-2z=-19
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I would use elimination by multiplying eqn two by 2, and eqn 2 by 4, then make your x's cancel
so -4x-4y+3z=-3 after multiplying equation 2 by 2?
i mean -4x-4y+6z=-6
2*(-2x+2y+3z=3) -4x+4y+6z = 6
Wow I wrote the problem down wrong in so many ways :p oh well. Alright, so now -4x+4y+6z = 6 into -x+3y-2z=-19 and get rid of the x, yeah?
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No, you have to multiply the 3rd eqn by 4
I came up with 4x+12y-12z=-114
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